February 13, 2012, 12:07:45 AM *
Welcome, Guest. Please login or register.

Login with username, password and session length
 
   Home   Help Login Register  
Pages: [1]   Go Down
  Print  
Author Topic: Putter Face Balance Point: A Technical Perspective  (Read 3748 times)
MentorSports
Golf Addict
****

MoJo: +5/-0
Offline Offline

Posts: 429

MentorSports


« on: May 25, 2007, 04:28:41 PM »

In recent years, the concept of a putter's face balance point as a technical specification has increased in perceived importance for fitting a particular type of putter to a particular golfer. Terms like "face-balanced", "toe hang", and "toe flow" are becoming more and more commonplace when discussing putters. Yet what causes a putter head to balance a certain way is still a mystery to many.

However, if we simply look at the two key factors, the shaft axis and putter head's center of gravity, and examine how they relate to each other, it's not only easy to understand why a putter balances a certain way, but it's also easy to calculate what the exact face balance point will be.

In its simplest terms, the face balance point is a reflection of how the head of a putter will situate itself if the head were allowed to freely rotate about its shaft axis when the axis is oriented horizontally with respect to the ground (i.e. perpendicular to the direction of gravity). In this equilibrium position, the center of gravity of the putter head aligns itself directly below the shaft axis as in the picture below. Note that the image below is from the perspective of looking straight down the shaft axis. The purple "triad" indicates the location of the putter head's center of gravity.



From this equilibrium position, the angle that the face forms with respect to the horizontal axis (i.e. the horizon) is termed the "toe hang". In order to calculate what this angle is in degrees, we need to determine the distance of the shaft axis and center of gravity of the head (CG) to the intersection of their orthogonal projections along the target line axis and the heel-toe axis, respectively. The image below illustrates these two distances (X and Y).



More simply put, the distance X is the shaft axis offset from the targetline axis and the distance Y is the CG setback from the heel-toe axis. In order to determine the amount of toe hang, we need to apply a little trigonometry. The tangent function gives us the ratio between X and Y based on a given angle formed by the hypotenuse of a right triangle with sides of distance X and Y. In order to calculate this angle based on the ratio between the lengths of sides of the right triangle, we apply the arc-tangent (or inverse tangent) function. In the picture above, the angle formed by the line between the shaft axis and the CG with respect to the heel-toe axis is:

Acg = arctan(Y/X)

However, this angle is not the same as the angle of toe hang when the head is allowed to rotate. The angle is actually 90 - Acg.  More simply the angle of the toe hang can be calculated by transposing X and Y in the equation above. The equation to calculate toe hang is thus:

Ath = arctan(X/Y)

On an Anser-style putter X and Y are generally equal. Therefore, the toe hang angle is calculated as:

Given: Y > 0
Ath = arctan(X/Y) = arctan(1) = 45 degrees

On a face-balanced putter, X is generally 0 (i.e. the shaft axis is inline with the head's CG along the targetline axis). Therefore, the toe hang is calculated as:

Ath = arctan(X/Y) = arctan(0) = 0 degrees

On a severely toe-heavy putter, Y is generally small and X is generally much larger. Therefore, the toe hang is calculated as:

Given: X >> Y

Ath = arctan(X/Y) = arctan() = 90 degrees

What this tells us is that the amount of toe hang that a putter exhibits is simply a reflection of the ratio between the shaft axis offset distance and the CG setback distance. This is why lie angle adjustments to putters, in general, will affect the face balance point of a putter. When a putter's shaft (or neck) is bent more upright, the distance X is increased. Therefore, the toe hang will also increase. When a putter is adjusted for a flatter lie angle, the distance X is decreased as is the amount of toe hang.

The type of neck (or lack thereof) that a putter has only matters to balance insofar as the neck positions the shaft axis in a particular position with respect to the head and its CG. For instance, as mentioned above, a standard plumber's neck positions the shaft axis such that the offset is nearly equal to the setback of the CG. This results in a 45 degree toe hang. However, there are also "long neck" versions of the plumber's neck. Since the neck is higher, the shaft axis intersects the head at a position that is closer to the center of the head (i.e. distance X is decreased). Therefore, the toe hang is also decreased--on some putters to the point of creating a neutral face-balance (i.e. 0 degree toe hang).
« Last Edit: May 25, 2007, 05:54:34 PM by MentorSports » Logged
XATHANASI
Read it. Roll it. Hole it.
GDS Guru
*****

MoJo: +6/-0
Offline Offline

Gender: Male
Posts: 2844



« Reply #1 on: May 25, 2007, 08:40:09 PM »

You are the man, Chin!

Thanks for the great info and diagrams!!
Logged

WITB

"I'm INSANE!!  Oh, wait... no I'm not."  X at lunchtime, 15 July 2007 
Dr.Green
GDS Guru
*****

MoJo: +222/-0
Offline Offline

Gender: Male


Posts: 11354



« Reply #2 on: May 27, 2007, 01:59:56 PM »

Very interesting - thanks for posting that.  clapping
Logged
drewspin
Judge Smails Courtroom
GDS Guru
***

MoJo: +83/-0
Offline Offline

Posts: 2427



« Reply #3 on: May 30, 2007, 07:33:02 PM »

Moojo for a great post!
Logged
Ankorgolf
GDS Guru
*****

MoJo: +0/-0
Offline Offline

Gender: Male
Posts: 682


wishoning my life away...


« Reply #4 on: June 02, 2007, 05:57:40 PM »

still trying to wrap my head around the math, but i got most of it!
thanx for the info!
Logged

MentorSports
Golf Addict
****

MoJo: +5/-0
Offline Offline

Posts: 429

MentorSports


« Reply #5 on: June 03, 2007, 11:21:55 AM »

still trying to wrap my head around the math, but i got most of it!
thanx for the info!

No need to get too caught up in the math. The main point of writing this is to show that the face balance point is purely based on the ratio between the shaft-axis offset and CG setback and that this principle applies to ALL putters. Keep this in mind if you ever happen to run across technical articles that make claims like:

"<Model X> is a face balanced design but I achieve face balance by gravity and not shaft axis."
Logged
Tigersworld
Weekend Golfer
*

MoJo: +0/-0
Offline Offline

Posts: 42


Sam Snead any generation!!!!


« Reply #6 on: June 26, 2007, 10:17:09 PM »

Nice work MentorSports. I myself have a question for you or anyone here I always wondered if you could offset a standard plumber's neck positions example lets add 15 grams or more in heel with tungsten screw in weights to make it a face balanced traditional plumber's neck putter. Lets get x to O another way?

Junior
Logged
MentorSports
Golf Addict
****

MoJo: +5/-0
Offline Offline

Posts: 429

MentorSports


« Reply #7 on: June 26, 2007, 11:29:45 PM »

Nice work MentorSports. I myself have a question for you or anyone here I always wondered if you could offset a standard plumber's neck positions example lets add 15 grams or more in heel with tungsten screw in weights to make it a face balanced traditional plumber's neck putter. Lets get x to O another way?

Junior

Assuming that you have a 330g head and a shaft axis offset of, say, 3/8th inch (.375") from the center of the head, this is how you would calculate where you would need to place that 15g. Here is the formula for calculating the center of mass:

Xcm = (m1x1 + m2x2) / (m1 + m2)

Let's say that x1,m1 represents the head and x2,m2 represents the additional mass (e.g. lead tape). In order to achieve a face balance, the center of mass of the entire system (Xcm) has to be shifted .375in toward the heel (i.e. to be inline with the shaft axis). For simplicity, we'll use the center of the head as the reference point. Therefore, x1 = 0.  So, here is the calculation:

Xcm = (m1x1 + m2x2) / (m1 + m2)
.375in = (0 + 15g * x2) / (330g + 15g)

Solve for x2:

x2 = .375in * 345g / 15g = 8.625 in

This means that the 15g additional mass has to be positioned 8.625" from the center of the head. With a standard size putter head (typically around 4.5" from heel to toe), how is this possible? It isn't. 15g simply won't do jack to move the center of mass enough to affect the face balance.

With the Maestro, you can achieve a face-balance with the plumber's neck by using a 110g T-Weight mounted with its center positioned about 1.5" from the center of the head. If the center of the weight is positioned at 1.5" from the center of the head, then the end of the weight cartridge is at 2.5" from the center of the head (because the T-Weight cartridge is 2" long). However, the Maestro head is only 4.5" from heel to toe. This means that even using a T-Weight, the cartridge will need to protrude .25" past the end of the heel in order for the Maestro to be face-balanced (2.5" - (4.5" / 2) = .25"). Although the T-Weight and even the lighter 50g S-Weight can make a significant change in the amount of toe-hang there is in the putter (depending on how you mount the weight cartridge), but you have to realize that shifting these weight cartridges around moves the center of mass of the entire system less than 3/8th of an inch.
Logged
drewspin
Judge Smails Courtroom
GDS Guru
***

MoJo: +83/-0
Offline Offline

Posts: 2427



« Reply #8 on: August 25, 2008, 11:09:39 PM »

Can someone make this a sticky - Chin has produced the best description of toe hang ever.
Logged
xxio
Judge Smails Courtroom
GDS Guru
***

MoJo: +8/-0
Online Online

Posts: 790


GolfShackChat!


« Reply #9 on: August 25, 2008, 11:38:37 PM »

Yes please.

Sir, Can I ask that this be posted on some other forums as well?
Logged
Dr.Green
GDS Guru
*****

MoJo: +222/-0
Offline Offline

Gender: Male


Posts: 11354



« Reply #10 on: September 06, 2008, 11:52:25 AM »

"This means that the 15g additional mass has to be positioned 8.625" from the center of the head. With a standard size putter head (typically around 4.5" from heel to toe), how is this possible? It isn't. 15g simply won't do jack to move the center of mass enough to affect the face balance."


I have never seen this phrase used in a scientific argument in my life .........I love it!  prop
Logged
Pages: [1]   Go Up
  Print  
 
Jump to:  

Powered by MySQL Powered by PHP Powered by SMF 1.1.14 | SMF © 2006-2011, Simple Machines LLC Valid XHTML 1.0! Valid CSS!
Page created in 0.296 seconds with 16 queries.